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15 Sep 2005, 16:54
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What is the perimeter of rhombus ABCD?
(1) Area of ABCD is 140cm^2
(2) Diagonal BD is 48 meters
(1) Area of ABCD is 140cm^2
(2) Diagonal BD is 48 meters
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THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.
If you would like to discuss this question please re-post it in the respective forum. Thank you!
To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
15 Sep 2005, 17:41
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C.
i) Area = 140 cm2
we cannot find side of the rhombus unless we know its hieght; therefore insufficient.
ii) rhombus diagonals are of different length. unless we know both diagonals we cannot find side.
together:
area = 1/2(d1 + d2)
140 = 1/2(48 + d2)
d2 = 232
as two diagonals in rhombus intersect at right angle (90 degrees)
side = sqrt (116^2 - 24^2)
permeter = side * 4
i) Area = 140 cm2
we cannot find side of the rhombus unless we know its hieght; therefore insufficient.
ii) rhombus diagonals are of different length. unless we know both diagonals we cannot find side.
together:
area = 1/2(d1 + d2)
140 = 1/2(48 + d2)
d2 = 232
as two diagonals in rhombus intersect at right angle (90 degrees)
side = sqrt (116^2 - 24^2)
permeter = side * 4
15 Sep 2005, 17:42
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c) both statements together are sufficient.
perimeter = ?
statement I: area of rhombus = 140 cm^2, ie. opposite diagonals (d1 and d2), d1*d2=280. that gives us little info about AB,BC or any other side. Insufficient
statement II: BD=48. Insufficient.
Together, we can calculate AC. Since the diagonals bisect at right angles, we can get each side by using pythagoras theorem.
perimeter = ?
statement I: area of rhombus = 140 cm^2, ie. opposite diagonals (d1 and d2), d1*d2=280. that gives us little info about AB,BC or any other side. Insufficient
statement II: BD=48. Insufficient.
Together, we can calculate AC. Since the diagonals bisect at right angles, we can get each side by using pythagoras theorem.
