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25 Jun 2007, 17:49
Kudos
Bookmarks
what is the prob of getting an ace and a heart when 7 cards are dealt from a 52 pack?
previously, the approach i've seen to solving this sorta q is:
(4C1)(13C1)(35C5)/(52C7)
but in this case, there is one card that is common b/w the ace denomination and the hearts suit - how do you account for this dependence?
one approach that comes to mind is to split the two cases and add them
- i.e one where the common card is not selected and the other when it is selected.
((4C1)(12C1)(35C5) + 1(51C6))/(52C7)
not sure if this approach is correct - also not sure what the question really means in this case?
TIA!
previously, the approach i've seen to solving this sorta q is:
(4C1)(13C1)(35C5)/(52C7)
but in this case, there is one card that is common b/w the ace denomination and the hearts suit - how do you account for this dependence?
one approach that comes to mind is to split the two cases and add them
- i.e one where the common card is not selected and the other when it is selected.
((4C1)(12C1)(35C5) + 1(51C6))/(52C7)
not sure if this approach is correct - also not sure what the question really means in this case?
TIA!
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25 Jun 2007, 18:44
Kudos
Bookmarks
now suppose, if the question asks "what is the probability of getting an ace OR a heart when 7 cards dealt from a 52 pack" (the difference here being OR instead of AND previously).
Here, one approach seems to be:
P = 1 - no aces or hearts in all 7 = 1 - (36/52)(35/51)(34/50)(33/49)(32/48)(31/47)(30/46)
Seems rather unweildy - is there a better approach? Thanks.
Here, one approach seems to be:
P = 1 - no aces or hearts in all 7 = 1 - (36/52)(35/51)(34/50)(33/49)(32/48)(31/47)(30/46)
Seems rather unweildy - is there a better approach? Thanks.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
