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What is the probability of rolling three fair dice and having none of

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Kudos [?]: 124181 [0], given: 12075

What is the probability of rolling three fair dice and having none of [#permalink]

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New post 06 Dec 2016, 11:09
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85% (00:53) correct 15% (01:22) wrong based on 78 sessions

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Kudos [?]: 124181 [0], given: 12075

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Kudos [?]: 1049 [0], given: 325

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Re: What is the probability of rolling three fair dice and having none of [#permalink]

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New post 07 Dec 2016, 11:14
Bunuel wrote:
What is the probability of rolling three fair dice and having none of the three dice show a prime number?

A. 5/8
B. 1/8
C. 1/36
D. 1/108
E. 1/216


There are 3 non prime numbers in a dice - { 1, 4, 6 }
Probability of getting a Non Prime number in a single throw is = \(\frac{3}{6} = \frac{1}{2}\)

So, The probability of getting none of the three dice show a prime number is \((\frac{1}{2})^3\)

Hence, answer will be (B) \(\frac{1}{8}\)
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Kudos [?]: 1049 [0], given: 325

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Re: What is the probability of rolling three fair dice and having none of [#permalink]

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New post 03 Aug 2017, 03:18
Probability of non prime nos to appear in 3 rolls
1-P(3 prime nos appear)=1-1/2*1/2*1/2=7/8.
So in that case probability of prime nos not to appear in 3 rolls
=1-7/8=1/8
Option B.

Kudos [?]: 2 [0], given: 166

Re: What is the probability of rolling three fair dice and having none of   [#permalink] 03 Aug 2017, 03:18
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