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25 Jul 2019, 01:27
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:17) correct
27%
(01:18)
wrong
based on 85
sessions
History
Date
Time
Result
Not Attempted Yet
What is the probability that the product of two integers (not necessarily different integers) randomly selected from the numbers 1 through 20, inclusive, is odd?
(A) 0
(B) 1/4
(C) 1/2
(D) 2/3
(E) 3/4
(A) 0
(B) 1/4
(C) 1/2
(D) 2/3
(E) 3/4
25 Jul 2019, 02:03
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For getting odd number by multiplying two numbers, both numbers should be odd:
—> 10 odd numbers from 1 to 20, inclusive.
“‘Not necessarily different numbers “ means that the number picked is placed again
Probability= (10/20)(10/20)= (1/2)*(1/2)=1/4
The answer choice is B
Posted from my mobile device
—> 10 odd numbers from 1 to 20, inclusive.
“‘Not necessarily different numbers “ means that the number picked is placed again
Probability= (10/20)(10/20)= (1/2)*(1/2)=1/4
The answer choice is B
Posted from my mobile device
25 Jul 2019, 03:05
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Bunuel
What is the probability that the product of two integers (not necessarily different integers) randomly selected from the numbers 1 through 20, inclusive, is odd?
(A) 0
(B) 1/4
(C) 1/2
(D) 2/3
(E) 3/4
(A) 0
(B) 1/4
(C) 1/2
(D) 2/3
(E) 3/4
total odd from 1 to 20 ; 10
so P ; 10/20 * 10/20 ; 1/4
because odd * odd = odd
IMO B
