What is the range of 30 consecutive even numbers?

Question

A. 54 
B. 56 
C. 58 
D. 60 
E. 62

saswata4s · Answer

It should be (n-1)d; 
i.e. (30-1)*2 = 58; 
Answer C.

deepthit · Answer

let 2 be the first number 
nth number is = a+(n-1)d = 2 +(30-1)2 = 60

Range = lasst number - first number = 60 - 2 = 58

BrentGMATPrepNow · Answer

We can also solve this question without using a formula. 
Instead, we'll look for a pattern.

Let 2 be the first even number and go from there.

1st even number = 2 = 2( 1 )
2nd even number = 4 = 2( 2 )
3rd even number = 6 = 2( 3 )
4th even number = 8 = 2( 4 )
.
.
.
30th even # = 2( 30 ) = 60

Range = 60 - 2 = 58
Answer: C

Cheers,
Brent

Abhishek009 · Answer

The range of the 30 consecutive even numbers will be - { 2 , 4 , 6........... 54, 56 , 58 , 60 }

Thus we have a series range will be 60 - 2 = 58
  
Answer will be (C) 58

MathRevolution · Answer

==> The number of consecutive numbers become (last-first/2)+1=(range/2)+1. In other words, from (range/2)+1=30, you get range/2=29, range=2(29)=58.

The answer is C.
Answer: C

nks2611 · Answer

option C should be the answer 
it does not affect the result whatever no. we choose the range will be same for the consecutive even integers

JeffTargetTestPrep · Answer

If the first even number is n, then the second is n + 2 = n + 2(1), the third is n + 4 = n + 2(2), the fourth is n + 6 = n + 2(3), etc. As we can see, the 30th even number will be n + 2(29). Thus the range is n + 2(29) - n = 2(29) = 58.

Alternate Solution:
 
Let’s create a simple sequence of consecutive even numbers by letting 2 be the first number. Let’s use the formula for the nth term of an arithmetic sequence: a_n = a_1 + (n-1)d, in which n = 30 and the common difference d = 2. Thus, the 30th consecutive even number will be a_30 = 2 + (29)(2) = 60. (Note that if you can’t quickly recall the formula for the nth term of an arithmetic sequence, you can actually count this out on your fingers!) The formula for the range is Range = Highest value – Lowest value, and thus we have Range = 60 – 2 = 58.

Answer: C

kingyoungin211 · Answer

I have one minor confusion. I was wondering why aren't we including the number 0 in this range as well? 0 is an even number as well. Shouldn't the range be 60-0 instead of 60-2? Please help clear my doubt!

Bunuel · Answer

The range of any 30 consecutive even numbers will be 58. If we consider 0 to be the first number in the sequence, then 30th number will be 58. The range = 58 - 0 = 58.

bumpbot · Answer

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What is the range of 30 consecutive even numbers?

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What is the range of 30 consecutive even numbers?

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