==> The units digit of \(3^n\) is the repetition of \(3-->9-->7--->1-->3-->9-->7-->1\), so you get \(50=4*12+2\).

Thus, from \(3^5^0=3^4^*^1^2^+^2\) --> \(~3^2=~9\), the units digit becomes 9, and if you divide it by 4, from \(9=4*2+1\), the remainder becomes 1.

Therefore, the answer is B.

Answer: B

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