Bunuel
What is the remainder when the positive integer n is divided by 6?
(1) n when divided by 12 leaves a remainder of 1
(2) n when divided by 3 leaves a remainder of 1
Target question: What is the remainder when the positive integer n is divided by 6? Statement 1: n when divided by 12 leaves a remainder of 1USEFUL RULE #1: "
If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3
No onto the question...........
Statement 1 does not tell us the quotient, so let's just say that n divided by 12 equals k with remainder 1
So, we can write: n = 12k + 1, where k is some integer
We can also write 12k a different way: n = (6)(2)(k) + 1
Or n = (
6)(2k) + 1
As you can see, (
6)(2k) is a multiple of
6, which means
(6)(2k) + 1 is ONE MORE than a multiple of 6So, when (
6)(2k) + 1 (aka n) is divided by 6,
the remainder must be 1Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: n when divided by 3 leaves a remainder of 1USEFUL RULE #2:
If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc. For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.
So, for statement 2, some possible values of n are: 1, 4, 7, 10, 13, 16, 19, 22, etc.
Let's TEST some values...
Case a: If n = 1, then
the remainder is 1, when n is divided by 6Case b: If n = 4, then
the remainder is 4, when n is divided by 6Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
RELATED VIDEO