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What is the remainder when x^2 - y^2 is divided by 3?

(1) x^2 is divisible by 6.

(2) y^2 is divisible by 9.


GH-04.24.13 | OE to follow
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avohden
What is the remainder when x^2 - y^2 is divided by 3?

(1) x^2 is divisible by 6.

(2) y^2 is divisible by 9.


GH-04.24.13 | OE to follow

Merging similar topics. Please refer to the solution above.
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Bunuel
What is the remainder when x^2 - y^2 is divided by 3?

(1) x^2 is divisible by 6. No info about y. Not sufficient.
(2) y^2 is divisible by 9. No info about y. Not sufficient.

(1)+(2) x^2 - y^2 = (multiple of 3) - (multiple of 3) = (multiple of 3), thus the remainder is zero. Sufficient.

Answer: C.

Why do we need information about y for 2)? Don't we need information about x^2 to determine the answer in (2)?
(x^2 - y^2)%3 = ((x^2)%3-(y^2)%3)%3
1) (0 - (y^2)%3)%3 = -(y^2)%3 | NS
2)((x^2)%3-0)%3 = (x^2)%3 | NS
(1)+(2): 0
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Official Explantion

Answer: C
- Each of the statements are insufficient on their own; we're looking for something concerning an expression with two variables, and each statement concerns only one of the variables.

Taken together, the statements are sufficient. If x^2 is divisible by 6, it is also divisible by all the factors of 6, including 3. The same reasoning applies to y^2. Since both x^2 and y^2 are divisible by 3, the difference between them is also divisible by 3, so the remainder is 0. Choice (C) is correct.
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Here is the rule that is quite helpful in problems such as these
for any integer X= 5p+2
and X=3P+2
the general expression for X becomes => X = 2+15P
as 15 is the LCM of 3 and 5
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