Last visit was: 13 Dec 2024, 16:05 It is currently 13 Dec 2024, 16:05
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
fauji
User avatar
IIM School Moderator
Joined: 05 Jan 2015
Last visit: 15 Jun 2021
Posts: 385
Own Kudos:
386
 []
Given Kudos: 214
Status:So far only Dreams i have!!
WE:Consulting (Computer Software)
Products:
Posts: 385
Kudos: 386
 []
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
garcmillan
Joined: 24 Sep 2015
Last visit: 15 Sep 2020
Posts: 71
Own Kudos:
105
 []
Given Kudos: 79
Location: Spain
Concentration: Strategy, Entrepreneurship
GPA: 3.9
WE:Management Consulting (Consulting)
Posts: 71
Kudos: 105
 []
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
Abhishek009
User avatar
Board of Directors
Joined: 11 Jun 2011
Last visit: 02 Oct 2024
Posts: 6,014
Own Kudos:
Given Kudos: 463
Status:QA & VA Forum Moderator
Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 6,014
Kudos: 4,952
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
fauji
User avatar
IIM School Moderator
Joined: 05 Jan 2015
Last visit: 15 Jun 2021
Posts: 385
Own Kudos:
386
 []
Given Kudos: 214
Status:So far only Dreams i have!!
WE:Consulting (Computer Software)
Products:
Posts: 385
Kudos: 386
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
My bad, Thanks for pointing it out.
Updated the Question now.
:thumbup:

garcmillan
When we are asked to determine a number to make an expression be the square, cube, etc of a positive integer, we always have to factorize that expression and then find the number that make the exponents of all factors equal 2 (square), 3 (cube), etc.

Let's go ahead. I will apply the mentioned steps to find the answer:

1) Factorize the expression:

From the given expression, only the number 168 can be factorized. The new expression would equal (2^3)*(3)*(7)*(k)^1/2

2) Find the number that makes the exponents of all factors equal 3 :

for the factor 2, we already have the cube of it in the expression, but for 3 and 7, we need additionally 3^2 and 7^2.

But since we are given the root of k, we would need the number to have the factors 3^4 and 7^4 so that in overall we can have (2^3)*(3^3)*(7^3)

So the right answer would be 3^4*7^4=194481

Since we don't have this number among the options, we can conclude that the problem hasn't been formulated correctly.

But going a bit further, if we calculate 3^2 and 7^2, then we get 441, which is option E

Therefore, we can assume that option E is the correct answer if expression had been 168*K and not 168*(K)^1/2

fauji: Please modify the problem expression accordingly!
User avatar
garcmillan
Joined: 24 Sep 2015
Last visit: 15 Sep 2020
Posts: 71
Own Kudos:
Given Kudos: 79
Location: Spain
Concentration: Strategy, Entrepreneurship
GPA: 3.9
WE:Management Consulting (Consulting)
Posts: 71
Kudos: 105
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ok, great. I edited my post :)

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Math Expert
97874 posts
Senior Moderator - Masters Forum
3116 posts