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sunniboy007
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What is the sum of all three digit numbers between 200 and 29 Feb 2004, 17:22
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What is the sum of all three digit numbers between 200 and 300 which when divided by 5 will leave a remainder of 3?

a.4990
b.5010
c.10020
d.9980
e. :stab



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What is the sum of all three digit numbers between 200 and 29 Feb 2004, 17:38
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Another good one !

Ans: B
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sunniboy007
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What is the sum of all three digit numbers between 200 and 29 Feb 2004, 17:40
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:lol: what was ur reasoning mate?
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cbrf3
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What is the sum of all three digit numbers between 200 and 29 Feb 2004, 18:08
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Between 200 & 300 we have a Arithmetic series whose 1st term is 203 and last term is 298, with a difference of 5 and there are 20 terms.....
So Sum = {2*a + (n-1)*d}*n/2
= {2*203 + (20-1)*5}*20/2
= 5010
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Paul
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What is the sum of all three digit numbers between 200 and 29 Feb 2004, 18:11
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Got B also in about 2 min.
The numbers you want is 203-208-213-218... 293-298. You will thus have 20 numbers to pick between 200 and 300 [(300 - 200) / 5 = 20]

Let's take care of the units digits first: You will have 10*3 and 10*8 = 30 + 80 = 110

The 10s digits: You each tens digit is repeated twice. ie 213 and 218. The formula to add up the tens digits is 10 * 2 * n(n + 1) / 2 = 20 * 9(9 + 1) / 2 = 20 * 45 = 900
NB 10 is the tens value so you have to multiply by 10. 2 is the fact that each tens digits is repeated twice. n(n + 1) / 2 is the formula to add up "n" consecutive numbers

Now, the hundreds digits: Since you have 20 numbers between 200 and 300 that you must pick, then 20 * 200 = 4000

Add up the total: 110 + 900 + 4000 = 5010



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