Bunuel
What is the units digit of (a + b)^2 – (a - b)^2, where a and b are non-negative integers?
(1) The difference between any two consecutive multiples of a is 5.
(2) b when multiplied by any even integer results in the same units digit, not necessarily equal to units digit of b.
\((a + b)^2 – (a - b)^2 = 4ab\)
Statement 1(1) The difference between any two consecutive multiples of a is 5.This statement means a = 5
The difference between two consecutive multiples of a number is the number itself.
For example, the difference between any two consecutive multiples of 2 is 2.
4ab = 4 * 5 * b , the unit digit is 0.
The statement is sufficient.
Statement 2(2) b when multiplied by any even integer results in the same units digit, not necessarily equal to units digit of b.If the unit digit of b is 0, multiplying any even integer will result in an unit digit of 0
Also if the unit digit of b is 5, multiplying any even integer will result in an unit digit of 0.
So we can conclude that b has 0 or 5 in its unit digit.
In both the cases, the unit digit of 4*a*b = 0.
Sufficient.
Option D