Bunuel
What is the units digit of (a + b)^2 – (a - b)^2, where a and b are non-negative integers?
(1) The difference between any two consecutive multiples of a is 5
(2) b when multiplied by any even integer results in the same units digit, not necessarily equal to units digit of b.
Are You Up For the Challenge: 700 Level QuestionsSolution
Step 1: Analyse Question Stem
• a and b are non-negative integer.
• We need to find the unit’s digit of \((a+b)^2 – (a -b)^2\)
o Now, \((a+b)^2 – (a -b)^2 = a^2 + b^2 +2*a*b – (a^2 + b^2 – 2*a*b) = 4*a*b\)
So basically, we need to find the unit’s digit of 4*a*b
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: The difference between any two consecutive multiples of a is 5
• It means a is a multiple of 5.
o So, unit’s digit of a can be either 0 or 5
• So, unit’s digit of 4*a*b = 4*unit’s digit of 5k* unit's digit of b
o So, unit’s digit of 4*a*b = 4*0* unit’s digit of b = 0
o Or, unit’s digit of 4*a*b =4*5*unit’s digit of b = 0* unit’s digit of b = 0
• Therefore, irrespective of unit’s digit of b, the units’ digit of 4*a*b will always be 0.
Hence, statement 1 is sufficient and we can eliminate answer option B, C and E.
Statement 2: b when multiplied by any even integer results in the same units digit, not necessarily equal to units digit of b.
• Thus, unit’s digit of b can be 0 or 5.
• So, unit’s digit of 4*a*b = 4*unit’s digit of a* units digit of b
o So, unit’s digit of 4*a*b = 4* unit’s digit of a*0 = 0
o Or, unit’s digit of 4*a*b =4*unit’s digit of a*5 = 0* unit’s digit of a = 0
• Therefore, irrespective of unit’s digit of a, the units’ digit of 4*a*b will always be 0.
Hence, statement 2 is also sufficient and the correct answer is
Option D.