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What is the value if x/y ? (1) (x/y)^2 = 1/81 (2) x^2/y^2 = 1/81

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What is the value if x/y ? (1) (x/y)^2 = 1/81 (2) x^2/y^2 = 1/81 [#permalink]

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New post 21 Sep 2010, 07:45
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Question Stats:

79% (00:22) correct 21% (00:28) wrong based on 19 sessions

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What is the value if x/y ?


(1) \((\frac{x}{y})^2 = \frac{1}{81}\)

(2) \(\frac{x^2}{y^2} = \frac{1}{81}\)
[Reveal] Spoiler: OA

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Re: What is the value if x/y ? (1) (x/y)^2 = 1/81 (2) x^2/y^2 = 1/81 [#permalink]

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New post 21 Sep 2010, 07:48
rxs0005 wrote:
What is the value if x/y


( x / y )^ 2 = 1 / 81

x^2 / y^2 = 1 / 81



Both statements say the same thing. (x/y) could be 1/9 or -1/9. Not enough information

Ans is (E)
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Re: What is the value if x/y ? (1) (x/y)^2 = 1/81 (2) x^2/y^2 = 1/81 [#permalink]

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New post 21 Sep 2010, 07:49
rxs0005 wrote:
What is the value if x/y


( x / y )^ 2 = 1 / 81

x^2 / y^2 = 1 / 81


Answer is E.

Both the statements are identical and yield x/y = -1/9 or 1/9

Thus both even taken together are insufficient.
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Re: What is the value if x/y ? (1) (x/y)^2 = 1/81 (2) x^2/y^2 = 1/81 [#permalink]

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Re: What is the value if x/y ? (1) (x/y)^2 = 1/81 (2) x^2/y^2 = 1/81   [#permalink] 23 Sep 2017, 18:56
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