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12 Apr 2023, 06:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
55% (01:38) correct
45%
(01:42)
wrong
based on 609
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of \(|1 - |2 - |3 - |4 – π||||\) ?
A. \(π\)
B. \(π - 1\)
C. \(π - 2\)
D. \(π - 3\)
E. \(4 - π\)
A. \(π\)
B. \(π - 1\)
C. \(π - 2\)
D. \(π - 3\)
E. \(4 - π\)
12 Apr 2023, 08:06
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Bunuel
I'd probably use ballparking on this question:
\(|1 - |2 - |3 - |4 – 3.1||||\)
\(|1 - |2 - |3 - |0.9||||\)
\(|1 - |2 - |3 - 0.9|||\)
\(|1 - |2 - |2.1|||\)
\(|1 - |2 - 2.1||\)
\(|1 - |-0.1||\)
\(|1 - 0.1|\)
\(|0.9|\)
\(0.9\)
Answer choice E.
If you feel compelled to prove that you can do the actual math even though it requires a bit more brainpower and doesn't get you any extra points, here you go:
\(|1 - |2 - |3 - |4 – π||||\)
\(4 – π\) is positive, so \(|1 - |2 - |3 - (4 – π)|||\)
\(|1 - |2 - |-1 + π|||\)
\(-1 + π\) is positive, so \(|1 - |2 - (-1 + π)||\)
\(|1 - |3 - π||\)
\(3 - π\) is negative, so \(|1 - (-3 + π)|\)
\(|4 - π|\)
\(4 - π\) is positive, so \(4 - π\)
Answer choice E.
ThatDudeKnowsBallparking
12 Apr 2023, 10:09
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Bunuel
\(4 – π\) is positive, so
\(|1 - |2 - |3 - |4 – π||||\)
\(|1 - |2 - |3 - (4 – π)|||\)
\(|1 - |2 - |3 - 4 + π|||\)
\((3 - 4 + π)\) is positive, so
\(|1 - |2 - (3 - 4 + π)||\)
\(|1 - |2 - 3 + 4 - π||\)
(2 - 3 + 4 - π) is negative, therefore |2 - 3 + 4 - π| = -(2 - 3 + 4 - π)
\(|1 - (-(2 - 3 + 4 - π))|\)
\(|1 + (2 - 3 + 4 - π)|\)
\(|1 + 2 - 3 + 4 - π|\)
\(|4 - π|\)
\(4 – π\) is positive, so
\(|4 – π| = 4 – π\)
Option E
