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Bunuel
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Solution



Given:
    • We are given an expression \((a \sqrt{5}+b \sqrt{5}) ^2\)

To find:

    • We need to find the value of the expression \((a \sqrt{5}+b \sqrt{5}) ^2\).
      o \((a \sqrt{5}+b \sqrt{5}) ^2\) = \([ \sqrt{5}(a + b)] ^2\)
      o = \(5(a + b) ^2\)

Thus, we only need to find the value of (a + b) to find the value of the expression \((a \sqrt{5}+b \sqrt{5}) ^2\).

Statement-1: a - b =5

The value of a-b can be 5 for various values of a and b. And, different values of a and b will result in a different value of a + b.

Let us see some examples:
    • For, a=6 and b=1, a-b=5 and a + b = 7
    • For, a=7 and b=2, a-b=5 and a + b = 9

Thus, Statement 1 alone is not sufficient to answer the question.

Statement-2:a (a + b) = 81- b (a + b)

Let us simplify the expression “a (a + b) = 81- b (a + b)”.
    • \(a^2+ ab = 81- b^2-ab\)
    • \(a^2+b^2+2ab= 81\)
    • \((a + b) ^2 = 9^2\)
    • \(a + b= 9\)

We can find the value of (a + b) from statement 2. Hence, we can also find the value of \((a \sqrt{5}+b \sqrt{5}) ^2\).

Thus, Statement 2 alone is sufficient to answer the question.

Hence, the correct answer is option B.

Answer: B
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