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mandy
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HowManyToGo


Picked (3)

N is 4 as explained in the prev post.
Now since the numbe is divisible by 11.
[M + 9 + 4 + 4 + 8 ] - [ 3 + 0 + 8 + 5 + N ] = 11K ( K IS AN INTEGER )
M + 25 - 16 - N = 11K
M - N + 9 = 11K
M + 5 = 11K

Since M IS less than 10 , k = 1.
Only M = 6 satisfies

HMTG.


HMTG, Can you be more explicit, what does M = 6 satisfy.
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mandy
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HowManyToGo
mandy

If M39048458N is divisible by 8 & 11; Where M & N are single digit integers?


(1) 7, 8 (2) 8, 6
(3) 6, 4 (4) 5, 4

(5) Can 't be determined


Picked (3)

N is 4 as explained in the prev post.
Now since the numbe is divisible by 11.
[ = 11K ( K IS AN INTEGER )
M + 25 - 16 - N = 11K
M - N + 9 = 11K
M + 5 = 11K

Since M IS less than 10 , k = 1.
Only M = 6 satisfies

HMTG.
plz HMTG where do you get :[M + 9 + 4 + 4 + 8 ] - [ 3 + 0 + 8 + 5 + N ] i don 't really understand how do you group them
i thought it was going to be the difference between odd and even
thanks


regards


mandy
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Folaa3
I plugged in numbers
for 11 - Subtract the sum of the even digits from the sum of the odd digits; if the difference, including 0, is divisible by 11, the number is also.
Never heard of that rule. How could you apply this rule for 121, 1221?

Another rule for 11 is: if the sum of the digits in even places is equal to the sum of the digits in odd places, than the number is divisible by 11, but I'm surprised at why this rule doesn't work here. Could somebody explain why?
[/quote]
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Folaa3
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Dilshod
Folaa3
I plugged in numbers
for 11 - Subtract the sum of the even digits from the sum of the odd digits; if the difference, including 0, is divisible by 11, the number is also.
Never heard of that rule. How could you apply this rule for 121, 1221?

Another rule for 11 is: if the sum of the digits in even places is equal to the sum of the digits in odd places, than the number is divisible by 11, but I'm surprised at why this rule doesn't work here. Could somebody explain why?
[/quote]

Dilshod, here is one link to divisibility rules
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Divisibility by 11 :

A number is divisible by 11 if the difference b/w the sum of digits on the odd places and the sum of digits on the even places is a multiple of 11.

eg 1331 = (1+3) - (3 +1 ) = 0 a multiple of 11.
92939 = ( 9 + 9 + 9 ) - ( 2 + 3 ) = 22 a multiple of 11.

Just to confirm 92939/11 = 8449.

HMTG.



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