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25 Jan 2022, 07:30
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Difficulty:
35%
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Question Stats:
72% (02:11) correct
28%
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based on 132
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What is the value of \(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!}\) ?
A. \((n+12)(n+15)\)
B. \((n+11)(n+12)\)
C. \((n+10)(n+13)\)
D. \((n+10)(n+15)\)
E. \((n+9)(n+12)\)
A. \((n+12)(n+15)\)
B. \((n+11)(n+12)\)
C. \((n+10)(n+13)\)
D. \((n+10)(n+15)\)
E. \((n+9)(n+12)\)
25 Jan 2022, 08:10
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Asked: What is the value of \(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!}\) ?
\(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!} = \frac{(n+13)! (1+ n+14)}{(n+11)!(1 + n+12)} = \frac{(n+13)(n+12)(n+15)}{(n+13)} = (n+12)(n+15)\)
IMO A
\(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!} = \frac{(n+13)! (1+ n+14)}{(n+11)!(1 + n+12)} = \frac{(n+13)(n+12)(n+15)}{(n+13)} = (n+12)(n+15)\)
IMO A
02 Apr 2022, 00:04
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Kinshook
Asked: What is the value of \(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!}\) ?
\(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!} = \frac{(n+13)! (1+ n+14)}{(n+11)!(1 + n+12)} = \frac{(n+13)(n+12)(n+15)}{(n+13)} = (n+12)(n+15)\)
IMO A
\(\frac{(n+13)!+(n+14)!}{(n+11)!+(n+12)!} = \frac{(n+13)! (1+ n+14)}{(n+11)!(1 + n+12)} = \frac{(n+13)(n+12)(n+15)}{(n+13)} = (n+12)(n+15)\)
IMO A
Can anyone explain this?
