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gluon
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Whatever
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I: Ins: K > -3
II: Ins: K <=0
Together: Ins: we have range -3 < r <=0

Ans. E
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gluon
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Guys my sincerest apologies. There was a copy and paste error in the post.

It should be:

(2) k^4 ≤ 0

Please reconsider your solutions.
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Whatever
gluon
Guys my sincerest apologies. There was a copy and paste error in the post.

It should be:

(2) k^4 ≤ 0

Please reconsider your solutions.

K = 0, hence answ. is B


I second that with "whatever" ..
k^4 cannot be negative as the even power is awlays +ve or 0.. Hence k^4 has to be 0. Hence k = 0.
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gluon
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Thanks guys, yes the OA is B.

That k^4 ≤ 0 was driving me nuts. How the heck can k^4 < 0?
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gluon
Thanks guys, yes the OA is B.

That k^4 ≤ 0 was driving me nuts. How the heck can k^4 < 0?


:-) Yes.... k^4 can not be less than zero.

- Brajesh
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gluon
What is the value of the integer k?
(1) k + 3 > 0
(2) k^4 ≤ 0


1) not sufficient since k can be any value
2) only integer that make this stmt true is 0
i get B since any raising anything to an even power will generate a positive value (i.e. fraction or int)
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St1:
k > -3. Insufficient. Can be any value above -3.

St2:
k^4 <0> 0. Sufficient.

Ans B
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actually got it from ur first post.

S1: k could be anything above -3. So negative, positive, fraction, etc... no help here.


S2: k^4 will ALWAYS be positive unless it is 0, in which case it is just 0.

any negative to an even power is always positive. so k^4<=0... it has to be zero. k can't be any negative or positive value.


Ans B.



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