BrentGMATPrepNow
What is the value of x?
(1) \(x^2-10x=24\)
(2) \(\frac{4x}{x^2-2x}=\frac{2}{5}\)
Target question: What is the value of x? Statement 1: x² - 10x = 24 Since we have a quadratic equation here, let's set it equal to zero by subtracting 24 from both sides of the equation.
When we do this we get: x² - 10x - 24 = 0
Factor: (x - 12)(x + 2) = 0
So, EITHER
x = 12 OR
x = -2Since we can’t answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: 4x/(x² - 2x) = 2/5Cross multiply to get: (2)(x² - 2x) = (4x)(5)
Simplify: 2x² - 4x = 20x
Subtract 20x from both sides: 2x² - 24x = 0
Factor: 2x(x - 12) = 0
At this point, it certainly LOOKS like EITHER
x = 0 OR
x = 12. However, we must consider the fact that, in the original equation we have a
rational expression in which x appears in both the numerator and denominator.
Now notice what happens if we plug x = 0 into the original equation.
We get: 4(0)/(0² - 2(0)) = 2/5, and upon simplification we get: 0/0 = 2/5, which is definitely not true.
In other words, x = 0 is NOT a solution to the original equation, which means
x = 12 is the only possible solution.
Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: BCheers,
Brent