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14 Jul 2022, 02:00
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D
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Difficulty:
35%
(medium)
Question Stats:
52% (00:36) correct
48%
(00:41)
wrong
based on 97
sessions
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What is the value of x^2 - y^2 ?
(1) x + y = 2x
(2) x - y = 0
(1) x + y = 2x
(2) x - y = 0
14 Jul 2022, 07:03
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The theory involved is the difference of squares.
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04 Apr 2023, 22:05
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Question: What is \(x^2 - y^2\) ?
Recall that \(x^2 - y^2 = (x + y)(x - y)\)
(1)\( x + y = 2x\)
\(y = 2x - x\)
\(y = x\)
If \(x = y\), then \(x^2 - y^2 = x^2 - x^2 = 0 \)
Sufficient alone
(2) \(x – y = 0\)
\(x^2 - y^2 = (x + y)(x - y) = (x + y) * 0 = 0\)
Sufficient alone
Answer (D)
