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20 Sep 2017, 22:51
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When a certain rectangle is divided in half, two squares are formed. If each of these squares has perimeter 48, what is the perimeter of the original rectangle?
(A) 96
(B) 72
(C) 36
(D) 24
(E) 12
(A) 96
(B) 72
(C) 36
(D) 24
(E) 12
21 Sep 2017, 01:21
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Bunuel
When a certain rectangle is divided in half, two squares are formed. If each of these squares has perimeter 48, what is the perimeter of the original rectangle?
(A) 96
(B) 72
(C) 36
(D) 24
(E) 12
(A) 96
(B) 72
(C) 36
(D) 24
(E) 12
Let each side of the square formed by dividing the rectangle be x.
Perimeter of the square = 4x=48
x=12
Perimeter of rectangle = 2(2x+x) =6x = 72
Answer B
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21 Sep 2017, 01:21
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If the rectangle is divided into squares of perimeter 48, the side of the square is 12.
Since the rectangle is formed by adding two squares, the sides
of the rectangle are 24 and 12 respectively.
The perimeter of this rectangle is 2(length + breadth) = 2(24 + 12) = 72(Option B)
Since the rectangle is formed by adding two squares, the sides
of the rectangle are 24 and 12 respectively.
The perimeter of this rectangle is 2(length + breadth) = 2(24 + 12) = 72(Option B)
