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# When n = 100x + 10y + z, function f is defined as f(n) =

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Director
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When n = 100x + 10y + z, function f is defined as f(n) = [#permalink]

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06 Dec 2005, 07:56
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When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

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Auge um Auge, Zahn um Zahn !

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SVP
Joined: 24 Sep 2005
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06 Dec 2005, 08:16
gamjatang wrote:
When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

notice 9= 3^2 --> the only possible difference between f(v) and f(t) is of 3^y ....f(v) contains 3^(y+2) ...powers of 2 and 5 in both functions f() are the same

----> u= 100x+10y+z and v= 100x+10(y+2) +z
----> v-u= 10*2= 20

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VP
Joined: 30 Sep 2004
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06 Dec 2005, 08:54
laxieqv wrote:
gamjatang wrote:
When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

notice 9= 3^2 --> the only possible difference between f(v) and f(t) is of 3^y ....f(v) contains 3^(y+2) ...powers of 2 and 5 in both functions f() are the same

----> u= 100x+10y+z and v= 100x+10(y+2) +z
----> v-u= 10*2= 20

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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

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Director
Joined: 14 Sep 2005
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Kudos [?]: 215 [0], given: 0

Location: South Korea

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07 Dec 2005, 08:05
bewakoof wrote:
laxieqv wrote:
gamjatang wrote:
When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

notice 9= 3^2 --> the only possible difference between f(v) and f(t) is of 3^y ....f(v) contains 3^(y+2) ...powers of 2 and 5 in both functions f() are the same

----> u= 100x+10y+z and v= 100x+10(y+2) +z
----> v-u= 10*2= 20

u are GENIIUS!

Yes she is.

The OA is 20.
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Auge um Auge, Zahn um Zahn !

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Manager
Joined: 20 Nov 2005
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07 Dec 2005, 08:38
crap, I could never get that.
Would this be considered medium difficulty or hard?

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Intern
Joined: 22 Mar 2005
Posts: 39

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08 Dec 2005, 12:04
Got 20 as well. Only way to increase 9 fold is using 3^2 which means y has increased by 2 and 10*2 = 20.

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Director
Joined: 14 Sep 2005
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Kudos [?]: 215 [0], given: 0

Location: South Korea

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09 Dec 2005, 10:38
crap, I could never get that.
Would this be considered medium difficulty or hard?

I'd say, this question falls in the "super hard" category.
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09 Dec 2005, 11:17
gamjatang wrote:
crap, I could never get that.
Would this be considered medium difficulty or hard?

I'd say, this question falls in the "super hard" category.

Do you get this type of questions in the real test.
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hey ya......

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09 Dec 2005, 11:17
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