took a bit of observation.
1. (remainder / divisor) = decimal part.
2. say you are dividing 10 by 6, remainder is 4 now to further divide 4 we do (4/6) which gives us the decimal part in the quotient.
Notice the remainder 4 is a single digit, we want double digit remainder, we can multiple 2 to both numerator and denominator as multiplying same multiple in numerator and denominator do not change the fraction so (4 *3 /6*3) = (12 /18 ) = ( remainder / divisor )...so we have our 1st 2 digit remainder which is 12 , now likewise we can find the last 2 digit remainder possible which is 4* 24 .
so possible 2-digit remainders are 4*3, 4*4, 4*5, .......4*24.
same logic applies to this question
Bunuel
When positive integer x is divided by positive integer y, the result is 59.32. What is the sum of all possible 2-digit remainders for x/y?
A. 560
B. 616
C. 672
D. 728
E. 784