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Mean of A = (20+P+80)/3
=(100+P)/3

Median of B = average of middle two numbers (3+5)/2=4

Now, as mentioned in the question "when the mean of the Set A is divided by the median of the Set B, the result is 15.25"
Hence, ((100+P)/3) / 4 = 15.25
=> (100+P)/12=15.25.
=> 100+P = 183
P=83

Now, Mean of B = (1+3+5+23)/4 = 32/4 = 8.

We need remainder when P^4 = 83 is divided by 8.
I used binomial's theorem to express 83 as (80+3)^4.
Expanding the same we will get (80^4 + 4(80^3)(3) + 6(80^2)(32) + 4(80)(3^3) + 3^4)
The remainder will be dependent on the last term which is 3^4 = 81.
When we divide 81/8 we get a remainder 1. and the other terms of the expression we get the remainders as 0 when divided by 8.

Hence Answer should be A: 1
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Given in the question:-

Set A = {20, P, 80}
and Set B = {1, 3, 5, 23}

now, median of Set B = (3+5)/2 = 4

Now given,
Mean of Set A/Median of Set B = 15.25
i.e. Mean of Set A/4 = 15.25
so, Mean of A = 15.25 * 4 = 61
(20 + P + 80)/ 3 = 61
100 + P = 183
so, P = 83

Now, mean of Set B = (1+3+5+23)/4 = 8

Now, 83/8 = 10 as quotient and 3 as remainder

so, 3^4 = 81 = 1 = (Mod 8)

Final answer:-Option (A) 1
Bunuel
Set A = {20, P, 80}
Set B = {1, 3, 5, 23}

When the mean of the Set A is divided by the median of the Set B, the result is 15.25. What is the remainder when P^4 is divided by the mean of the Set B?

A. 1
B. 3
C. 5
D. 6
E. 7


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