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LCM is 60, so it is equivalent to say that:
A produces 6 units every hour
B produces 10 units every hour

So in 3 hours we have 3(6+10) = 48 units of 60
So B needs to produce 12 remaining units in x hours

10 units in 1 hour
12 units in x hour
x = 1,2 hour or 1hour and 12 min
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Solution



Given:
In this question, we are given
    • Working independently, machine A can complete a piece of work in 10 hours.
    • Working independently, machine B can complete a piece of work in 6 hours.
    • Both machines worked together for 3 hours, and then machine A stopped working.
    • The remaining work was completed by machine B, working alone.

To find:
We need to determine
    • The extra time taken by machine B, to complete the remaining work.

Approach and Working:
Let us assume the total work to be the LCM (10, 6, 3) = 30 units

In 10 hours, machine A does 30 units of work.
    • Hence, in 1 hour, machine A does \(\frac{30}{10}\) = 3 units of work

In 6 hours, machine B does 30 units of work.
    • Hence, in 1 hour, machine B does \(\frac{30}{6}\) = 5 units of work

In 1 hour, machine A and machine B together can finish (3 + 5) = 8 units

As they worked for 3 hours together, total work completed in those 3 hours = (8 x 3) units = 24 units.
    • Remaining work after 3 hours = (30 – 24) units = 6 units

As machine B completed the remaining work alone, the extra time taken beyond 3 hours = \(\frac{6}{5}\) hours = 1 hour 12 minutes.

Hence the correct answer is Option B.

Answer: B


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When working independently, machine A can complete a piece of work in 10 hours, and machine B can complete the same wok in 6 hours. Both machines worked together for 3 hours, and then Machine A stopped working. How much more time did machine B take to complete the remaining work ?

    A. 1 hour
    B. 1 hours 12 minutes
    C. 1 hour 20 minutes
    D. 1 hour 48 minutes
    E. 2 hours


Machine A’s rate is 1/10, and machine A worked for 3 hours. Machine B’s rate is 1/6. If we let n = the extra time that machine B worked, then machine B worked for (3 + n) hours. We can create the equation:

(1/10)(3) + (1/6)(3 + n) = 1

3/10 + (3+n)/6 = 1

Multiplying by 30, we have:

9 + 15 + 5n = 30

5n = 6

n = 6/5 = 1 1/5 = 1 hour and 12 minutes.

Alternate Solution:

Working alone, Machine A and Machine B can complete 1/10 and 1/6 of the job in one hour, respectively. Together, they complete 1/10 + 1/6 = 16/60 = 4/15 of the job in one hour. Since they work for 3 hours, 3 x 3/15 = 12/15 = 4/5 of the job is completed and 1 - 4/5 = 1/5 of the job remains. Since Machine B completes the whole job in 6 hours, it will complete 1/5 of the job in 6 x 1/5 = 6/5 hours or, equivalently, 1 hour and 12 minutes.

Answer: B
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When working independently, machine A can complete a piece of work in 10 hours, and machine B can complete the same wok in 6 hours. Both machines worked together for 3 hours, and then Machine A stopped working. How much more time did machine B take to complete the remaining work ?

    A. 1 hour
    B. 1 hours 12 minutes
    C. 1 hour 20 minutes
    D. 1 hour 48 minutes
    E. 2 hours


To read all our articles: Must Read Articles and Practice Questions to score Q51

Let total work be 30 Units (LCM of 10 & 6)

So, Efficiency of A = 3units/hr & Efficiency of B = 5units/hr , Combined efficeincy of A & B is 8 units/hr
Quote:
Both machines worked together for 3 hours
So, work completed by A & B in 3 hours is 24 units and 6 units are left for B to complete...

So, Time required by B to complete the work is \(\frac{6}{5} = 1\) hours \(12\) Minutes, Answer must be (B)
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