Solution
Given:In this question, we are given
• Working independently, machine A can complete a piece of work in 10 hours.
• Working independently, machine B can complete a piece of work in 6 hours.
• Both machines worked together for 3 hours, and then machine A stopped working.
• The remaining work was completed by machine B, working alone.
To find:We need to determine
• The extra time taken by machine B, to complete the remaining work.
Approach and Working:Let us assume the total work to be the LCM (10, 6, 3) = 30 units
In 10 hours, machine A does 30 units of work.
• Hence, in 1 hour, machine A does \(\frac{30}{10}\) = 3 units of work
In 6 hours, machine B does 30 units of work.
• Hence, in 1 hour, machine B does \(\frac{30}{6}\) = 5 units of work
In 1 hour, machine A and machine B together can finish (3 + 5) = 8 units
As they worked for 3 hours together, total work completed in those 3 hours = (8 x 3) units = 24 units.
• Remaining work after 3 hours = (30 – 24) units = 6 units
As machine B completed the remaining work alone, the extra time taken beyond 3 hours = \(\frac{6}{5}\) hours = 1 hour 12 minutes.
Hence the correct answer is Option B.
Answer: B