Hi All,
We're asked which number is divisible by 2, 3, 4, and 6 but is NOT divisible by 5. This question is built around several 'rules of division' patterns - and if you know those patterns, then you can use some 'math shortcuts' on this question and save some calculation time.
To start, we're looking for a number that is NOT divisible by 5.... so if a number 'ends' in a 0 or 5, then we can eliminate it. Eliminate Answers C and E.
Next, any number that is divisible by 4 is ALSO divisible by 2.... and any number that is divisible by 6 is ALSO divisible by 2 and 3. This ultimately means that we need to check 3 of the answers (Answers A, B and D) and find the one that is divisible by both 4 and 6...
Answer A: 138/4 = 34.5.... not evenly divisible by 4. Eliminate Answer A
Answer B: 644/4 = 161...... 644/6 = 107.333.... not evenly divisible by 6. Eliminate Answer B
You might also recognize that you can use the "rule of 3" to eliminate Answer B. The digits of 644.... 6, 4 and 4 add up to 6+4+4 = 14. Since 14 is NOT divisible by 3, 644 is NOT divisible by 3 either.
There's only one answer left...
Final Answer:
GMAT assassins aren't born, they're made,
Rich