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22 Mar 2018, 23:43
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E
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Difficulty:
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Question Stats:
82% (00:43) correct
18%
(00:57)
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Which of the following expressions is equivalent to \((s^2 + 9)^{(-\frac{1}{2})}\) ?
A. \(-\frac{s^2 + 9}{2}\)
B. \(-\frac{1}{\sqrt{s^2 + 9}}\)
C. \(-\sqrt{s^2 + 9}\)
D. \(\frac{1}{s+3}\)
E. \(\frac{1}{\sqrt{s^2 + 9}}\)
A. \(-\frac{s^2 + 9}{2}\)
B. \(-\frac{1}{\sqrt{s^2 + 9}}\)
C. \(-\sqrt{s^2 + 9}\)
D. \(\frac{1}{s+3}\)
E. \(\frac{1}{\sqrt{s^2 + 9}}\)
23 Mar 2018, 00:19
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Bunuel
Which of the following expressions is equivalent to \((s^2 + 9)^{(-\frac{1}{2})}\) ?
A. \(-\frac{s^2 + 9}{2}\)
B. \(-\frac{1}{\sqrt{s^2 + 9}}\)
C. \(-\sqrt{s^2 + 9}\)
D. \(\frac{1}{s+3}\)
E. \(\frac{1}{\sqrt{s^2 + 9}}\)
A. \(-\frac{s^2 + 9}{2}\)
B. \(-\frac{1}{\sqrt{s^2 + 9}}\)
C. \(-\sqrt{s^2 + 9}\)
D. \(\frac{1}{s+3}\)
E. \(\frac{1}{\sqrt{s^2 + 9}}\)
As the calculation we're asked to do is straightforward, we'll just do it.
This is a Precise approach.
A negative power of a number is the reciprocal of that number to the positive power.
A power of 1/2 is the same as a square root. So:
So, \((s^2 + 9)^{(-\frac{1}{2})} = \frac{1}{(s^2 + 9)^{\frac{1}{2}}}\) = \(\frac{1}{\sqrt{s^2 + 9}}\)
(E) is our answer.
23 Mar 2018, 00:30
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Bunuel
Which of the following expressions is equivalent to \((s^2 + 9)^{(-\frac{1}{2})}\) ?
A. \(-\frac{s^2 + 9}{2}\)
B. \(-\frac{1}{\sqrt{s^2 + 9}}\)
C. \(-\sqrt{s^2 + 9}\)
D. \(\frac{1}{s+3}\)
E. \(\frac{1}{\sqrt{s^2 + 9}}\)
A. \(-\frac{s^2 + 9}{2}\)
B. \(-\frac{1}{\sqrt{s^2 + 9}}\)
C. \(-\sqrt{s^2 + 9}\)
D. \(\frac{1}{s+3}\)
E. \(\frac{1}{\sqrt{s^2 + 9}}\)
\((s^2 + 9)^{(-\frac{1}{2})}\) = 1/ \((s^2 + 9)^{(\frac{1}{2})}\) = \(\frac{1}{\sqrt{s^2 + 9}}\)
