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08 Dec 2014, 06:24
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
76% (00:46) correct
24%
(00:49)
wrong
based on 216
sessions
History
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Not Attempted Yet
Tough and Tricky questions: Combinations.
Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word BANANA could be arranged to create a six-letter code?
A) 6!
B) 6! − (3! + 2!)
C) 6! − (3! × 2!)
D) 6!/(3! + 2!)
E) 6!/(3! × 2!)
Kudos for a correct solution.
Source: Chili Hot GMAT
08 Dec 2014, 08:04
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Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word BANANA could be arranged to create a six-letter code?
A) 6!
B) 6! − (3! + 2!)
C) 6! − (3! × 2!)
D) 6!/(3! + 2!)
E) 6!/(3! × 2!)
Number of letters in word 'BANANA' = 6.
The letters 'A' and 'N' appear 3 times and 2 times respectively in the word 'BANANA'.
Therefore the mathematical solution for number of ways that the letters of the word BANANA can be arranged to create six-letter code
= 6!/(3!*2!)
Answer: E
A) 6!
B) 6! − (3! + 2!)
C) 6! − (3! × 2!)
D) 6!/(3! + 2!)
E) 6!/(3! × 2!)
Number of letters in word 'BANANA' = 6.
The letters 'A' and 'N' appear 3 times and 2 times respectively in the word 'BANANA'.
Therefore the mathematical solution for number of ways that the letters of the word BANANA can be arranged to create six-letter code
= 6!/(3!*2!)
Answer: E
08 Dec 2014, 21:16
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BANANA - six letters can be arranged in 6! ways
since 'A' repeats 3 times and 'N' repeats 2 times, we need to divide the 6! ways by 3! and 2! to adjust repetition.
6!/(3!*2!)
Ans. E) 6!/(3! × 2!)
since 'A' repeats 3 times and 'N' repeats 2 times, we need to divide the 6! ways by 3! and 2! to adjust repetition.
6!/(3!*2!)
Ans. E) 6!/(3! × 2!)
