WORDS PROBLEMS

Question

hello 
canyone knows how to solve this one and the equations to put thanks 


In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000

sparky · Answer

15,000 + (x-1980 -1)*2,450 = 20,000 + (x-1980 -1)*2,000

x is the year

thearch · Answer

that makes 1992 the answer...I hope!

HowManyToGo · Answer

I vote for D.

John earns 5000 less than Don, and he makes closes the gap by 450 a year.
So he would take 5000/450 =   years to close this gap , where   = next highest integer.

HMTG.

krisrini · Answer

My answer is 1992, and my approach to the problem was same as HMTG

Thanks

cloudz9 · Answer

if x is the number of years that John has to wait to get paid more than Don..we have to find x when
15000 + 2450x > 20000 + 2000x
450x > 5000
x > 11.1

thus the first year will be after 12 years, i.e. 1992

bmwhype2 · Answer

thanks. simple yet couldnt think of it at the moment,

saurster · Answer

For this kind of a problem, my tendency is to write an algebraic equation, but its better to solve this with the logic HTMG used, making up the deficit of $5000 in $450 installments/year....and computing how long it'll take to do this.

Himalayan · Answer

it should be simple.

15,000 + n (2,450) = 20,000 + n (2,000)
n = 11.xxxx

since now it is 1980, it is 1992 (12 more years from now) to have John's salary to be greater than donna's.

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