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Working at their respective constant rates, Paul, Abdul and Adam alone
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23 Sep 2011, 01:35
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Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam? (A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47 Innovative Solutions will be highly Appreciated.
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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23 Sep 2011, 02:01
We can solve the problem just by calculating the work done in 1 hr.
Work done by adam in 1 hr is 1/5. total work done by all three in 1 hr is (1/3 + 1/4 +1/5) = 47/60
so, fraction of work done by Adam = (1/5)/(47/60) = 12/47.
Option B.




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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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23 Sep 2011, 01:56
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Let the total work be 60 units. Pual does 60/3 =20 units of work per hr. abdul does 15 units per hr and adam does 12 units per hr. If all work together they do (20 + 15 + 12) units per hr = 47 units per hr. So the time taken to finish the work = 60/47 hrs. adam will do 60/47 * 12 units of work in 60/47 hr . fraction of work adam does =work done by adam / total work >( 60/47 *12)/60 =12/47 Answer B



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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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23 Sep 2011, 02:04
Work is measured in job per unit time. Let j be job Rate of work done by Paul= J/3= 0.33J Abdul= J/4= 0.25J Adam=J/5=0.2J Relative rate w.r.t Adam Paul= 0.33/0.2=1.65 Abdul=0.25/2=1.25 Adam=1 Hence relative proportion of work done= 1.65:1.25:1 Adam's share= 1/(1.65+1.25+1)=1/3.9 Closest option is 12/47 B
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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23 Sep 2011, 02:10
vishal4584 wrote: We can solve the problem just by calculating the work done in 1 hr.
Work done by adam in 1 hr is 1/5. total work done by all three in 1 hr is (1/3 + 1/4 +1/5) = 47/60
so, fraction of work done by Adam = (1/5)/(47/60) = 12/47.
Option B. Your Solution Here seems to be good. But I would like To clarify Some silly doubts: If all three work together to finish the work, what fraction of the work will be done by Adam Question asks us to find : Ratio of work done by adam/ Work Done by all three . But you have based ur calculations on only 1 hour. Why is that? Infact, all three take longer than 1 hour to finish the work.



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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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25 Sep 2011, 10:29
In this approach we consider the work as some unit of work = 1 PaulAbdulAdam Rate1/31/41/5 when they all work together their combined rate = 1/3+1/4+1/5 = 47/60 time taken by them to finish to unit work = 60/47 hours work done by adam in 60/47 hours = (60/47)*(1/5) = 12/47 fraction of work done by adam = adam's work / total work = (12/47) / 1 = 12/47 So coming back to your question its 1 unit of work here. thats why the total work they can do= 1. you can consider the work done as some 'w' still the answer would be same. Answer is B. GMATPASSION wrote: vishal4584 wrote: We can solve the problem just by calculating the work done in 1 hr.
Work done by adam in 1 hr is 1/5. total work done by all three in 1 hr is (1/3 + 1/4 +1/5) = 47/60
so, fraction of work done by Adam = (1/5)/(47/60) = 12/47.
Option B. Your Solution Here seems to be good. But I would like To clarify Some silly doubts: If all three work together to finish the work, what fraction of the work will be done by Adam Question asks us to find : Ratio of work done by adam/ Work Done by all three . But you have based ur calculations on only 1 hour. Why is that? Infact, all three take longer than 1 hour to finish the work.



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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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25 Sep 2011, 10:50
Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Step 1: find the individual rates by finding the inverse of the times  Paul: 1/3, Abdul: 1/4, Adam: 1/5 Step 2: add the rates  1/3 + 1/4 + 1/5 = 47/60 Step 3: the inverse of the combined rate above tells you the time. i.e. takes 60/47 hours to finish the job together Step 4: apply the 60/47 hours to Adam's rate to find his share of work  W = 1/5*60/47 = 12/47
Answer B.



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Working at their respective constant rates, Paul, Abdul and Adam alone
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20 Mar 2016, 03:37
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Innovative Solutions will be highly Appreciated. Rate of work done Paul 1/3 Abdul 1/4 Adam 1/5 Total rate of work 1/3+1/4+1/5=47/60 Total work done is inverse of total rate of work=60/47 Adams contribution will be Total work done X Adams's rate of work 60/47X1/5=12/47



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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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27 Sep 2016, 02:16
[1/5]/[1/3+1/4+1/5] = 60 / (5*47) = 12/47 is the answer



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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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16 Aug 2017, 08:46
Say there are 60 units of work to be done.So Paul takes 3 hrs => in 1 hr he completes 20 units of work Abdul takes 4 hrs => in 1 hr he completes 15 units of work Adam takes 5 hrs => in 1 hr he completes 12 units of work In 1 hour all together can complete 47 units of work. Hence time taken to complete 60 units of work is 60/47 hours. Now in 60/47 hours Adam completes (12*60)/47 units of work. Hence his contribution would be (12*60)/(47*60) which is 12/47.
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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15 Mar 2019, 07:42
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Innovative Solutions will be highly Appreciated. We can let t = the time during which all three people work together; thus, the combined work is: (1/3)t + (1/4)t + (1/5)t = (20/60)t + (15/60)t + (12/60)t = (47/60)t Thus, Adam completed (1/5)t/[(47/60)t] = 60/(47 x 5) = 12/47 of the job. Answer: B
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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09 Jun 2019, 07:38
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Innovative Solutions will be highly Appreciated. Solution Name,R,T,W Paul: 1/3, 3 Abdul: 1/4, 4 Adam: 1/5, 5 Method 1: Fractions Total Rate = 1/3 + 1/4 + 1/5 = (20+15+12)/60 = 47/60 Fraction of work done by Adam: (60/47) * (1/5) = 12/47 Method 2: LCM Method Rate for Paul: Abdul: Adam: Total 20:15:12: 47 Fraction of work done by Adam: 12/27
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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09 Aug 2019, 09:22
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Innovative Solutions will be highly Appreciated. One approach is to assign a "nice" value to the entire job. That is, a value that works well with the given information (3, 4, and 5 hours). The least common multiple of 3, 4 and 5 is 60. So, let's say the ENTIRE job consists of making 60 widgets. If Paul can complete the job (make 60 widgets) in 3 hours, then his RATE of work = 20 widgets PER HOUR If Abdul can make 60 widgets in 4 hours, then his RATE of work = 15 widgets PER HOUR If Adam can make 60 widgets in 5 hours, then his RATE of work = 12 widgets PER HOUR So, if they work TOGETHER, their combined RATE = 20 + 15 + 12 = 47 widgets PER HOUR So, for every HOUR that passes, the GROUP can make 47 widgets We also know that, for every HOUR that passes, the Adam can made 12 widgets (since his RATE of work = 12 widgets PER HOUR) This means that, when the 3 people work together, Adam makes 12/ 47 of the widgets Answer: B Cheers, Brent
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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18 Aug 2019, 10:02
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Innovative Solutions will be highly Appreciated. combined rate ; 1/3+1/4+1/5 ; 47 /60 so time 60/47 and rate of Adam ; 1/5 so work done ; 60/47 * 1/5 ; 12/47 IMO B
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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18 Aug 2019, 10:19
GMATPASSION wrote: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction of the work will be done by Adam?
(A) 1/4 (B) 12/47 (C) 1/3 (D) 5/12 (E) 20/47
Innovative Solutions will be highly Appreciated. Given: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. Asked: If all three work together to finish the work, what fraction of the work will be done by Adam? Ratio of work done by Paul: Abdul: Adam = 1/3: 1/4:1/5 = 20:15:12 Fraction of the work done by Adam \(= \frac{12}{(20+15+12)} = \frac{12}{47}\) IMO B
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Re: Working at their respective constant rates, Paul, Abdul and Adam alone
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