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x = 0.57y9. If y denotes the thousandth digit in the decimal represent

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Bunuel
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x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   10 Oct 2019, 23:08
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x = 0.57y9. If y denotes the thousandth digit in the decimal representation of x above, what digit is y?

(1) If x were rounded to the nearest tenth, the result would be 0.6.

(2) If x were rounded to the nearest hundredth, the result would be 0.58.
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   11 Oct 2019, 01:38
Bunuel wrote:
x = 0.57y9. If y denotes the thousandth digit in the decimal representation of x above, what digit is y?

(1) If x were rounded to the nearest tenth, the result would be 0.6.

(2) If x were rounded to the nearest hundredth, the result would be 0.58.


#1
insufficient
as y value is not clear
#2
again insufficient as y = 5,6,7,8,9 insuffiient
from 1 &2
nothing in common
IMO E
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   13 Oct 2019, 03:25
Bunuel wrote:
x = 0.57y9. If y denotes the thousandth digit in the decimal representation of x above, what digit is y?

(1) If x were rounded to the nearest tenth, the result would be 0.6.

(2) If x were rounded to the nearest hundredth, the result would be 0.58.


(1) If x were rounded to the nearest tenth, the result would be 0.6.

Since tenth's digit is 7, For any value of y, x will always be rounded off to 0.6
Possible values of y = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} --> Insufficient

(2) If x were rounded to the nearest hundredth, the result would be 0.58.
--> Possible values of y = {5, 6, 7, 8, 9} --> Insufficient

Combining (1) & (2),
--> Common values of y = {5, 6, 7, 8, 9} --> Insufficient

IMO Option E
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   11 Apr 2023, 06:45
How is the tenth digit 7? Isn't it 5?

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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   11 Apr 2023, 07:50
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DelademAnku wrote:
How is the tenth digit 7? Isn't it 5?

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Yes, the tenths digit is 5, not 7. The pervious post has a typo.
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   12 Apr 2023, 14:18
Then that means 1. Is sufficient cos rounding to the nearest tenth gives you 0.6 cos 7 is Larger than 5. Or?

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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink] New post   13 Apr 2023, 00:07
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DelademAnku wrote:
x = 0.57y9. If y denotes the thousandth digit in the decimal representation of x above, what digit is y?

(1) If x were rounded to the nearest tenth, the result would be 0.6.

(2) If x were rounded to the nearest hundredth, the result would be 0.58.

Then that means 1. Is sufficient cos rounding to the nearest tenth gives you 0.6 cos 7 is Larger than 5. Or?

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When rounding 0.57y9 to the nearest tenth, the value of y does not affect the result because the hundredths digit 7 is already greater than or equal to 5. Therefore, the tenths digit (5) rounds up to 6. Thus, 0.57y9 rounded to the nearest tenth is 0.6.

Rounding rules

Rounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.

Example:
5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5.
5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5.
5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink]
13 Apr 2023, 00:07
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Bunuel
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