happyapple123
What is the range for the inequality x^2 - 4x <0?
The solution is 0<x<4.
But I think the solution should be x<0 x>4.
Can someone please assist? Thanks.
Hi happyapple123,
\(x^2 - 4x <0 => x (x - 4) < 0\)
This means either \(x < 0\) or \((x - 4) < 0\) but not both, because if both are negative then
multiplication of two negative numbers is positive so the equation will not be true.
Now, if
\(x < 0\) then \((x - 4)\) is also less than 0, which makes both negative, so this cannot be true.
for example,
if \(x = -1\), then \((x - 4) => (-1 - 4) = -5 < 0\)
=> so, \((-1) * (-5) = 5 > 0\), so equation doesn't agree.
Hence, only \((x - 4) < 0\) but \(x > 0\) which means
\(0 < x < 4\)