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priyankurml
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Himalayan
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Bluebird
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I agree with Himalaya... I got E.

From stmt [1] we know that the difference between the tens digit can only be 3 or 2. Insufficient.

Stmt [2] tells us nothing because we already know that the units digit of x minus the units digit of y is 7, which is greater than 3. Insufficient.

Putting both together gives us nothing.

Answer: E
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grad_mba
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go with C

st1 - either 2 or 3 INSUFF

st2 - Insuff by itself

st1 and st2 - only 2 is poss SUFF
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lets say x = AB y = CD

According to 1)

AB
-CD
-----
27

We have to find A - C
Now there two possibilities 3 and 2.

So A is insufficient

According to 2

B-D > 3 which is excellent news. Because it tells us that there is no carry over from the A to B in order to subtract D. Thus It is sufficient to know that A-C = 2.

Hence answer is C .
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In my copy I've got the answer E, but not sure whether it's OA!! Thanks for the discussion....
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sludge
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Alternatively, let 10u+t and 10m+n denote our two numbers

1) says 10u+t - (10m+n) = 27

2) says t-n > 3

expand 1: 10(u-m) + (t - n) = 27

27-10(u-m) = t - n

27-10(u-m) > 3

24 > 10(u-m)


Now, we only know that 10(u-m) needs to be LARGER than 24, but we don't have an upper bound. Therefore, E.
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priyankurml
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sludge
Alternatively, let 10u+t and 10m+n denote our two numbers

1) says 10u+t - (10m+n) = 27

2) says t-n > 3

expand 1: 10(u-m) + (t - n) = 27

27-10(u-m) = t - n

27-10(u-m) > 3

24 > 10(u-m)


Now, we only know that 10(u-m) needs to be LARGER than 24, but we don't have an upper bound. Therefore, E.


Thanks, I proceeded in this way...
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iamba
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Let x=10m+n
and y=10p+q

From 1, x-y = 10(m-p)+(n-q) = 27
This can be expressed as 10*3-3 or as 10*2+7

So, the diff of units digits can be 7 or -3
Diff of tens digits can be 2 or 3

Second stmt says diff is greater than 3. So it has to be 7.
So Diff of tens digits should be 2

Answer is both together are suff
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x and y are 2-digt integers. What is the difference between two tens' digit?
1). x-y=27
2). Units' digit of x minus the units' digit of y is greater than 3

______________________________________________________
Set:
x = AB
Y = CD

1) Stated that X-Y = 27; thus, we know that B-D=7. Therefore, the possible values for (B,D) are (0,3) (7,0) (8,1) (9,2). If (B,D) = (0,3), then we know that we have to subtract 1 from A. If (B,D) = (7,0) OR (8,1) OR (9,2), we do not substract 1 from A. This means that we cannot determine A-C. This statement is INSUFFICIENT.

2) Stated that B-D > 3. We only know the unit digit substraction, we don't know the tens digits; thus, INSUFFICIENT.

Together, we know that B-D > 3. This eliminate the possible value of (B,D) = (0,3). Since (B,D) not equal to (0,3), we know that we don't have to substract one from A; thus, A-C must be 2. SUFFICIENT.

Let me know if there is any mistake.



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