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25 Oct 2007, 15:12
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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X and Y are integers. Is Y an even integer?
(1) Y^2 + X = X^2 - 2Y
(2) X is an odd integer
(1) Y^2 + X = X^2 - 2Y
(2) X is an odd integer
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25 Oct 2007, 15:24
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o = odd
e = even
either
y=e and x=e
y=o and x=o
y=e and x=o
y=o and x=e
statement 1
y^2 + x = x^2 - 2*y
y=e and x=e ---> e+e = e-e ---> true
y=o and x=o ---> o+o = o-e ---> false
y=e and x=o ---> e+o = o-e ---> true
y=o and x=e ---> o+e = e-e ---> false
either way --> y is even !
sufficient
statement 2
knowing that x is odd will not help determine ---> y
insufficient
the answer is (A)
e = even
either
y=e and x=e
y=o and x=o
y=e and x=o
y=o and x=e
statement 1
y^2 + x = x^2 - 2*y
y=e and x=e ---> e+e = e-e ---> true
y=o and x=o ---> o+o = o-e ---> false
y=e and x=o ---> e+o = o-e ---> true
y=o and x=e ---> o+e = e-e ---> false
either way --> y is even !
sufficient
statement 2
knowing that x is odd will not help determine ---> y
insufficient
the answer is (A)
25 Oct 2007, 15:32
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KillerSquirrel
Killersquirell, i disagree. If you separate the Y's and the X's then you have 2y+y^2=x^2-x
2y is always even, but if y is 3 then it is not even anymore.
2*3+3^2 is odd. Therefore y can't be odd.
Am i judging it wrong guys?
