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Q: |A-B|?

1. A=2, B=5; A+B=7; |A-B|=3
A=2, B=3; A+B=5; |A-B|=1
NS

2. A=2,B=2; |A-B|=0
A=2,B=3; |A-B|=1
A=3,B=2; |A-B|=1
A=3,B=3; |A-B|=0
NS

Combining 1 and 2;
A=2,B=3; A+B=5; |A-B|=1
A=3,B=2; A+B=5; |A-B|=1

Sufficient.

Ans: "C"
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statement 1: A + B is a prime integer- if sum of two prime integers is prime, one of them has to be 2( Prime nos. are all odd, except 2, and odd +odd is even, so to make A + B, at least one has to be even. only even prime is 2) However, there is no way to find the value of other prime, it can be any prime upto infininty, so a single value of |A-B| cant be established. Hence, insufficient.
2. Only integers less than 5 which are prime are 2 and 3. Absolute value of difference therefore has only one possible value (i.e.1)
Hence sufficient.
Answer : B
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1. (GC) A and B are prime integers. What is |A - B|?
(1) A + B is a prime integer
(2) Both A and B are less than 5

my solution:
(1) A+B is a prime integer
One of the prime number is 2 and the other could be any prime number such that A+B is also a prime number (for ex: 3,5,7,11 etc). Therefore |A-B| could be any value => not sufficient
(2) Both A and B are less than 5
A and B could be 2 or 3, and A and B could be the same prime number . Therefore |A+B| could be 0 or 1. => not sufficient
(1 and 2)
A and B are 2 different prime numbers less that 5 (that means 2 and 3) => sufficient
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Answer should be C for this one.

Question doesnt say that A and B are different.

1. Not sufficient

2,5 diff 3
2,11 diff 9

2. Not sufficient

2,2 diff 0
3,3 difff 0
2 3 diff 1

together we know that a and b has to different , because a+b is prime. so sufficient.

Answer C.
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Spidy001
Answer should be C for this one.

Question doesnt say that A and B are different.

1. Not sufficient

2,5 diff 3
2,11 diff 9

2. Not sufficient

2,2 diff 0
3,3 difff 0
2 3 diff 1

together we know that a and b has to different , because a+b is prime. so sufficient.

Answer C.

If A=2, B=2 , |A-B| = 0
If A=2/3 , B=2/3, |A-B|= 1

So how is answer is B ? Should be C ?
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jlgdr
A and B are prime integers. What is |A - B|?

(1) A + B is a prime integer
(2) Both A and B are less than 5

From 1. The value of A,B can be anything 2,3 or 2,5 or 2,17 so on.... Adding A+B we get a prime number with different values of |A-B|. Not sufficient.
From 2. Value of A,B must be 2,3 or 3,2 mod of their difference will always be 1. sufficient
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If x and y are prime numbers, what is the value of |x-y|?

(1) x + y is a prime number
(2) Both x and y are less than 5

1-x+y =PN 2 & 3, 2& 5, 2& 11, 2&17 etc
x,y<5 i.e. 2&3
B alone answers the question
How come OA is C ?
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if x and y are prime number than combinations can be 2 and 3, 3 and 5

1: x+y is a prime number
it is possible in many cases
a) x=2,y=3
b) x=2,y=7
Not sufficient
2: Not sufficient
Combining both we see only one case which is x=2 and y=3
So Answer is C
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