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Difficulty:
75%
(hard)
Question Stats:
44%
(03:04)
correct 56%
(02:35)
wrong
based on 16
sessions
History
Date
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x is a prime number and y is a positive integer. If x and y have only two common factors, what is the numerical value obtained when the least common multiple of x and y is divided by the greatest common divisor of x and y?
(1) y is divisible by 4 positive integers and has 2 prime factors, one of which is 5. (2) y is equal to 3 times the highest number that divides both x and y.
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x is a prime number and y is a positive integer. If x and y have only two common factors, what is the numerical value obtained when the least common multiple of x and y is divided by the greatest common divisor of x and y?
(1) y is divisible by 4 positive integers and has 2 prime factors, one of which is 5. (2) y is equal to 3 times the highest number that divides both x and y.
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Hi
That’s a mouthful so let’s walk through step by step.
“x is a prime number and y is a positive integer. If x and y have only two common factors” – that just means that GCD of x and y is x (two common factors are 1 and prime x).
“numerical value obtained when the least common multiple of x and y is divided by the greatest common divisor of x and y”. LCM of x and y is y, so our problem boils down to finding out the value of \(\frac{y}{x}\).
(1) y is divisible by 4 positive integers and has 2 prime factors, one of which is 5.
\(y = p^1*q^1\), where p and q are primes, one of which is equal to x. But we don’t know the value of x.
If x=5 then we have \(\frac{y}{x} = \frac{5*q}{5} = q\) (unknown second prime).
If x=q then \(\frac{y}{x} = \frac{5*q}{q} = 5\)
We can’t get exact value. Insufficient.
(2) y is equal to 3 times the highest number that divides both x and y.
That give us directly that \(y=3*x\). Hence \(\frac{y}{x} = \frac{3*x}{x} = 3\). Sufficient.
B
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.