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14 Jun 2023, 08:00
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Difficulty:
95%
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40% (02:46) correct
60%
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wrong
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x, y, and z are positive integers and \(x < y < z\). If \(x + y + z\) is an even number less than 15, is x equal to 2?
(1) The product of any two numbers of x, y, and z is an even number.
(2) One of x, y, and z is twice the one of the other numbers.
(1) The product of any two numbers of x, y, and z is an even number.
(2) One of x, y, and z is twice the one of the other numbers.
14 Jun 2023, 10:42
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For the first statement Given that all the numbers must be even and in increasing order with an even sum less than 15, two combinations are possible: 2,4,6 (Sum=12) or 2,4,8 (sum=14). In both situations, smallest number has to be 2. Hence A is alone sufficient. For the second statement, two cases are possible for an even sum (o,o,e) or (e,e,e) eg, (3,6,5) (sum=14) and of course the previous two combinations identified in statement 1. Thus B alone is not sufficient.
04 Jul 2023, 03:09
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Bunuel Could you please provide the solution?
For Statement 1:- Can't the solution be 3<4<6 ? The sum is also below 15. Also,The product of any two numbers of x, y, and z is an even number.
For Statement 1:- Can't the solution be 3<4<6 ? The sum is also below 15. Also,The product of any two numbers of x, y, and z is an even number.
