xyz? 1) xyz=1 2) xyz^21 pls, provide ur explanation

Question

xy>z?
1) xyz=1
2) xyz^2>1

pls, provide ur explanation.

ccax · Answer

(1) or (2) alone are clearly not sufficient. (1) xyz = 1 (2) xyz^2 > 1 Taken together: xyz^2 - xyz > 0 xyz (z-1) > 0 1 * (z-1) > 0 z > 1 So xy < 1 and xy < z. So it's C.

sherinaparvin · Answer

Nothing more to add.

C should be

foolbox · Answer

I'm very sad to be in a misconception. but, as you said xy<1, and z >1 then, xy<1 xy < z (N.S.) how is that? pls enlighten myself.

ccax · Answer

How is what? Which step didn't you understand?

foolbox · Answer

shouldn't the question be xyz? cause you figured out that xy<1, and z>1 => xy :oops:

ccax · Answer

Well it was you who wrote the question

But if I say that xyz is no.

gmatacer · Answer

Yeah I think I got question wrong Friend, Can we take of putting brackets in future ? I thought xyz^2 to be (xyz)^2 and got answer E

May be its just me ....

TeHCM · Answer

Great explanation, should be C

xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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