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# xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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Manager
Joined: 13 Mar 2006
Posts: 73
xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation [#permalink]

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23 Apr 2006, 04:15
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xy>z?
1) xyz=1
2) xyz^2>1

pls, provide ur explanation.
_________________

GMAT by 8th JUL

Manager
Joined: 20 Nov 2004
Posts: 108

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23 Apr 2006, 04:25
(1) or (2) alone are clearly not sufficient.

(1) xyz = 1
(2) xyz^2 > 1

Taken together:
xyz^2 - xyz > 0
xyz (z-1) > 0
1 * (z-1) > 0
z > 1

So xy < 1 and xy < z.

So it's C.
Intern
Joined: 20 Feb 2006
Posts: 45

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23 Apr 2006, 04:35
Nothing more to add.

C should be
Manager
Joined: 13 Mar 2006
Posts: 73
bad.... [#permalink]

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23 Apr 2006, 07:24
ccax wrote:
(1) or (2) alone are clearly not sufficient.

(1) xyz = 1
(2) xyz^2 > 1

Taken together:
xyz^2 - xyz > 0
xyz (z-1) > 0
1 * (z-1) > 0
z > 1

So xy < 1 and xy < z.

So it's C.

I'm very sad to be in a misconception.

but, as you said xy<1, and z >1
then, xy<1<z => xy < z (N.S.)

how is that? pls enlighten myself.
_________________

GMAT by 8th JUL

Manager
Joined: 20 Nov 2004
Posts: 108
Re: bad.... [#permalink]

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23 Apr 2006, 07:44
foolbox wrote:
how is that? pls enlighten myself.

How is what? Which step didn't you understand?
Manager
Joined: 13 Mar 2006
Posts: 73
... [#permalink]

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23 Apr 2006, 08:48
shouldn't the question be xy<z, instead of xy>z?

cause you figured out that xy<1, and z>1 => xy<z

god... know what i mean?
_________________

GMAT by 8th JUL

Manager
Joined: 20 Nov 2004
Posts: 108
Re: ... [#permalink]

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23 Apr 2006, 08:54
foolbox wrote:
shouldn't the question be xy<z, instead of xy>z?

Well it was you who wrote the question

But if I say that xy<z, then it means that the answer to the
question whether xy>z is no.
Senior Manager
Joined: 24 Jan 2006
Posts: 252

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24 Apr 2006, 07:22
Yeah I think I got question wrong

Friend, Can we take of putting brackets in future ? I thought xyz^2 to be (xyz)^2 and got answer E

May be its just me ....
VP
Joined: 06 Jun 2004
Posts: 1053
Location: CA

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29 Apr 2006, 00:38
Great explanation, should be C
_________________

Don't be afraid to take a flying leap of faith.. If you risk nothing, than you gain nothing...

29 Apr 2006, 00:38
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# xy>z? 1) xyz=1 2) xyz^2>1 pls, provide ur explanation

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