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02 Oct 2004, 00:07
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On another site, the answer to the following Data Sufficiency:
X is a prime number. What is X?
(1) X <15
(2) (X-2) is a multiple of 5
The answer purported to be E, because X could be 2 or 7, given that 5 and 0 are multiples of 5 (i.e. each 5 and 0 can be divided by 5 evenly).
This just seems wrong - that 0 is a multiple of all numbers - but wanted to sanity check this with a considerably more sophisticated site than the one I happenned to be on when I ran across this.
X is a prime number. What is X?
(1) X <15
(2) (X-2) is a multiple of 5
The answer purported to be E, because X could be 2 or 7, given that 5 and 0 are multiples of 5 (i.e. each 5 and 0 can be divided by 5 evenly).
This just seems wrong - that 0 is a multiple of all numbers - but wanted to sanity check this with a considerably more sophisticated site than the one I happenned to be on when I ran across this.
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02 Oct 2004, 00:17
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1. X is a prime number < than 15. It can be 2,3,5,7,11,or 13. Diff possible values for X. Hence Insuff.
2. X-2 = multiple of 5 => cn be 5, 10, 15, 20, 25...whatever. Now, say X-2 = 5 => X=3. say, X-2 = 10 => X=12. Different values for X. Hence Insufficient.
Combining both we have. X=3 prime number or say, X=12 not a prime number. Again many different values for X. Hence Insufficient. Hence E.
2. X-2 = multiple of 5 => cn be 5, 10, 15, 20, 25...whatever. Now, say X-2 = 5 => X=3. say, X-2 = 10 => X=12. Different values for X. Hence Insufficient.
Combining both we have. X=3 prime number or say, X=12 not a prime number. Again many different values for X. Hence Insufficient. Hence E.
02 Oct 2004, 21:27
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I agree with the fact that 0 is the multiple of all numbers.
So, from stmt 1 alone: X= 2, 3, 5, 7, 11, 13 : insufficient.
from stmt 2 alone: X= 2, 7, 17, 37..... insufficient
combining to two: it is 2 and 7. So again insufficient.
Hence E.
So, from stmt 1 alone: X= 2, 3, 5, 7, 11, 13 : insufficient.
from stmt 2 alone: X= 2, 7, 17, 37..... insufficient
combining to two: it is 2 and 7. So again insufficient.
Hence E.
