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nzgmat
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08^-5 -------- = ? .04^-4 A) 5/64 B) 5/32 C) 25/32 05 Nov 2004, 17:30
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.08^-5
-------- = ?
.04^-4

A) 5/64
B) 5/32
C) 25/32
D) 32/25
E) 50



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caribcon
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08^-5 -------- = ? .04^-4 A) 5/64 B) 5/32 C) 25/32 08 Dec 2004, 09:55
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Hi,
Can someone give me step by step instructions on how to solve this problem. Also supposed you have a problem like this:

10^-7 - 10^2

If you are under a time constraint how would you handle a problem like this.
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jinino
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08^-5 -------- = ? .04^-4 A) 5/64 B) 5/32 C) 25/32 08 Dec 2004, 13:51
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caribcon
Hi,
Can someone give me step by step instructions on how to solve this problem. Also supposed you have a problem like this:

10^-7 - 10^2

If you are under a time constraint how would you handle a problem like this.
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0.08^-5=(8/100)^-5=(100/8)^5
0.04^-4=(4/100)^-4=(100/8)^4

list out all the terms of [(100/8)^5]/[(100/4)^4], cancel 4 100s, take out 4s, and you will get 100/128 or 25/32

10^-7=(1/10)^7, 10^2=100, I guess then you just need to do the calculation even you do not have much time.
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08^-5 -------- = ? .04^-4 A) 5/64 B) 5/32 C) 25/32 10 Dec 2004, 13:07
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I did it like this:

First, I swapped them to get rid of the negative exponent. .04^4/.08^5.

Then I split the .08^5 into (.04x2)^5, which then became .04^5x2^5, so the whole fraction is now: .04^4/(.04^5x2^5), which then cancels down to 1/(.04x2^5) which is 1/1.28.

Now, I'm not worried about decimals in fractions, because I can clear them out by moving them away top and bottom. So the answer becomes 100/128, which reduces to 25/32.



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