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23 May 2017, 11:13
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Please note that a^-n = (1/a)^n and vice versa.
Thus, in case of (base)^exponent: if you do reciprocal of the base then the sign of exponent changes (positive will become negative and vice versa)
Here we have (1/2)^-3 = 2^3 = 8
and (1/4)^-2 = 4^2 = 16
Adding the two, 8+16 = 24
Thus, in case of (base)^exponent: if you do reciprocal of the base then the sign of exponent changes (positive will become negative and vice versa)
Here we have (1/2)^-3 = 2^3 = 8
and (1/4)^-2 = 4^2 = 16
Adding the two, 8+16 = 24
23 May 2017, 13:21
Kudos
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An intuitive way of dealing with negative sign "-" in exponents is to think of the negative sign "-" in exponents as a "flip" operation.
Problem: ((1/2)^-3)+((1/4)^-2))
Step 1: Apply the - sign and flip 1/2 and 1/4.
=(2^3)+(4^2)
Step 2: Apply the remaining exponent:
=8+16
=24
Problem: ((1/2)^-3)+((1/4^-2))
Step 1: Apply the - sign and flip 1/2 and 4
=(2^3)+(1/(1/4)^2)
Step 2: Apply the remaining exponent:
=8+(1/(1/16)
=8+16
Problem: ((1/2)^-3)+((1/4)^-2))
Step 1: Apply the - sign and flip 1/2 and 1/4.
=(2^3)+(4^2)
Step 2: Apply the remaining exponent:
=8+16
=24
Problem: ((1/2)^-3)+((1/4^-2))
Step 1: Apply the - sign and flip 1/2 and 4
=(2^3)+(1/(1/4)^2)
Step 2: Apply the remaining exponent:
=8+(1/(1/16)
=8+16
