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[(y^2)/2 - (y^2)/18]^1/2 =?

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[(y^2)/2 - (y^2)/18]^1/2 =?  [#permalink]

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New post 30 Jan 2020, 10:17
4
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

79% (01:15) correct 21% (01:25) wrong based on 53 sessions

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\(\sqrt{\frac{y^2}{2} - \frac{y^2}{18}} =\)?

(A) 0

(B) \(\frac{2|y|}{3}\)

(C) \(\frac{19y}{3}\)

(D) \(\frac{y\sqrt{3}}{6}\)

(E) \(\frac{y\sqrt{5}}{3}\)

Source: Master GMAT

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Re: [(y^2)/2 - (y^2)/18]^1/2 =?  [#permalink]

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New post 30 Jan 2020, 14:31
y^2(1/2-1/18)
y^2(4/9)
2y/3
B
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Re: [(y^2)/2 - (y^2)/18]^1/2 =?  [#permalink]

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New post 31 Jan 2020, 07:35
SajjadAhmad wrote:
\(\sqrt{\frac{y^2}{2} - \frac{y^2}{18}} =\)?

(A) 0

(B) \(\frac{2|y|}{3}\)

(C) \(\frac{19y}{3}\)

(D) \(\frac{y\sqrt{3}}{6}\)

(E) \(\frac{y\sqrt{5}}{3}\)

Source: Master GMAT


\(\sqrt{\frac{y^2}{2} - \frac{y^2}{18}} = \sqrt{\frac{9y^2}{18} - \frac{y^2}{18}} = \sqrt{\frac{8y^2}{18}} = \sqrt{\frac{4y^2}{9}} = |\frac{2y}{3}| = \frac{2}{3} * |y| \)

Ans: B
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Re: [(y^2)/2 - (y^2)/18]^1/2 =?   [#permalink] 31 Jan 2020, 07:35
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