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gmatxsurf
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gmatxsurf
Hi,

why 1/c = c/1 it equal to c^2 = 1 ???

thank you

Nice question

this is actually
\(\frac{1}{c}- \frac{c}{1} =0\)
\(\frac{1-c^2}{c }= 0\)
now c can not be zero since then it becomes NAn
so \(1-C^2 =0\)
or \(c^2 =1\)
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dep
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Also to add on
c = +1 or -1
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liusam
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Kudos to those answers :)