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# [n] = (1/n)^n for all integers n > 0. What is the value of [3] ?

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Joined: 02 Sep 2009
Posts: 57281
[n] = (1/n)^n for all integers n > 0. What is the value of [3] ?  [#permalink]

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22 Jul 2019, 01:30
00:00

Difficulty:

15% (low)

Question Stats:

100% (00:23) correct 0% (00:00) wrong based on 21 sessions

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$$\boxed {n}$$$$=(\frac{1}{n})^n$$ for all integers n > 0. What is the value of $$\boxed {3}$$ ?

A. $$\frac{1}{27}$$

B. $$\frac{1}{3}$$

C. $$1$$

D. $$3$$

E. $$27$$

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[n] = (1/n)^n for all integers n > 0. What is the value of [3] ?  [#permalink]

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22 Jul 2019, 02:30
Bunuel wrote:
$$\boxed {n}$$$$=(\frac{1}{n})^n$$ for all integers n > 0. What is the value of $$\boxed {3}$$ ?

A. $$\frac{1}{27}$$

B. $$\frac{1}{3}$$

C. $$1$$

D. $$3$$

E. $$27$$

Given: $$\boxed {n}$$$$=(\frac{1}{n})^n$$ for all integers n > 0.
Asked: What is the value of $$\boxed {3}$$

$$\boxed {3}=(\frac{1}{3})^3 = \frac{1}{27}$$

IMO A
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Re: [n] = (1/n)^n for all integers n > 0. What is the value of [3] ?  [#permalink]

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23 Jul 2019, 04:39
Re: [n] = (1/n)^n for all integers n > 0. What is the value of [3] ?   [#permalink] 23 Jul 2019, 04:39
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