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14 Apr 2008, 20:21
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1) The cost prices of 3 kinds of tea are 10$, 12$,16$ per bag. In what proportion should they be mixed so that the price of the mixture may be 14$ per bag?
1) 2:3:4
2) 1:2:3
3) 1:1:3
4) 1:1:2
5) 1:1:1
2) A loan is discharged in three equal installments of 2662$ each. If the rate of interest is 10%, Find the amount of loan?
Please explain the procedure for both.
1) 2:3:4
2) 1:2:3
3) 1:1:3
4) 1:1:2
5) 1:1:1
2) A loan is discharged in three equal installments of 2662$ each. If the rate of interest is 10%, Find the amount of loan?
Please explain the procedure for both.
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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14 Apr 2008, 20:48
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1) Multiply first one by 10, second one by 12, and third one by 16. Add all the three and check if it is divisible by 3 or not. Only Answer 3 will satisfy the answer.
2) Total Paid = 3*2662 = 7986
X + X*10/100 = 7986
1.1X = 7986
=> X = 7260
2) Total Paid = 3*2662 = 7986
X + X*10/100 = 7986
1.1X = 7986
=> X = 7260
14 Apr 2008, 20:54
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Value
1) if price of the mixture is $14, then sum of the mixture must be 126. lets check whether the sum is 126 or not.
with the ratio of 2:3:4, the actual sum is (2x10 + 3x12 + 4x16) = 120. so not suff.
2) if price of the mixture is $14 and the tees are in the ratio of 1:2:3, then sum of the mixture must be 84. lets check whether the sum is 84 or not.
with the ratio of 1:2:3, the actual sum is (1x10 + 2x12 + 3x16) = 82. so not suff.
3) similarly the sum must be 70.
actual sum = 10x1 + 12x1 + 16x3 = 70.
bingo...
4) cannot be
5) cannot be
so C.
Value
this more about PV concept.
assuming no advance payment, the loan amt = 2662/1.1 + 266/(1.1)^2 + 266/(1.1)^2 = 2420 + 2200 + 2000 = 6620
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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Thank you for understanding, and happy exploring!
