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27 Nov 2007, 12:59
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How many zeros do 10! end with?
Please explain your approach
Please explain your approach
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27 Nov 2007, 13:54
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2.
each "0" corresponds to 2*5
In 10! number of "2" is more than number of "5". And 10! contains two "5": 1*2*3*4*5*6*7*8*9*10
Therefore,
10! contains two zero
each "0" corresponds to 2*5
In 10! number of "2" is more than number of "5". And 10! contains two "5": 1*2*3*4*5*6*7*8*9*10
Therefore,
10! contains two zero
27 Nov 2007, 16:22
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bmwhype2
6!=720
From here I just multiplied it out til I got 362880*10. Which is going to give us 2 zeros. Took me about 1min.
Walkers approach is def. Much faster.
