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Bunuel
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Bunuel
\(1051^2 − 1049^2 = ?\)

A. 4
B. 16
C. 1050
D. 2100
E. 4200

\(1051^2 − 1049^2 =\)
\((1050 + 1)^2 - (1050 - 1)^2\)
\((1050 + 1 + 1050 - 1)(1050 + 1 - 1050 + 1)\)
\((2100)(2)\)
\(4200\) - E
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Bunuel
\(1051^2 − 1049^2 = ?\)

A. 4
B. 16
C. 1050
D. 2100
E. 4200

IMO the answer is option E

(1051)^2 - [(1051-2)^2]
Solving the equation will give us 4200.

But when I formed the equation:

(1050+1)^2 - [(1050-1)^2]
Im not getting the same Idk why. I tried it twice.

Posted from my mobile device
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ManyataM
Bunuel
\(1051^2 − 1049^2 = ?\)

A. 4
B. 16
C. 1050
D. 2100
E. 4200

IMO the answer is option E

(1051)^2 - [(1051-2)^2]
Solving the equation will give us 4200.

But when I formed the equation:

(1050+1)^2 - [(1051-2)^2]
Im not getting the same Idk why. I tried it twice.

Posted from my mobile device

Hi ManyataM,
The reason why you are getting a different answer is because your breakup is wrong.
If you use the below breakup, you can not apply \(a^2 - b^2 = (a+b)(a-b)\)
(1050+1)^2 - [(1051-2)^2]
Refer to the post just above yours. I hope that helps :)
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ManyataM
Bunuel
\(1051^2 − 1049^2 = ?\)

A. 4
B. 16
C. 1050
D. 2100
E. 4200

IMO the answer is option E

(1051)^2 - [(1051-2)^2]
Solving the equation will give us 4200.

But when I formed the equation:

(1050+1)^2 - [(1051-2)^2]
Im not getting the same Idk why. I tried it twice.

Posted from my mobile device

Hi ManyataM,
The reason why you are getting a different answer is because your breakup is wrong.
If you use the below breakup, you can not apply \(a^2 - b^2 = (a+b)(a-b)\)
(1050+1)^2 - [(1051-2)^2]
Refer to the post just above yours. I hope that helps :)

Hey.. Got my mistake. Thanks. I understood it. 🤟🏻
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GMAT 1: 760 Q51 V42
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\(a^2 - b^2 = (a - b)(a + b)\)

\(1051^2 - 1049^2 = (1051 - 1049)(1051 + 1049) = 2 * 2100 = 4200\)

Answer E
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