Bunuel wrote:

\(\sqrt{12} + \sqrt{108} + \sqrt{48} =\)

A. \(12\sqrt{3}\)

B. 24

C. \(12\sqrt{5}\)

D. \(48\sqrt{3}\)

E. \(\sqrt{168}\)

\(\sqrt{12} + \sqrt{108} + \sqrt{48} =\)

Put factors under the radical signs, looking for factors that are perfect squares.

Look also, and first, for a

common factor that is NOT a perfect square, one that will remain beneath the radical sign.

Check the answer choices for possible factors that are not perfect squares.

Here, choices are

\(\sqrt{3}\), \(\sqrt{5}\), and \(\sqrt{168}\)5 is not a factor at all. 168 is too great to work with. Ignore.

Try 3 under the radical sign.

Once you divide each number by 3, the remaining factor is a perfect square.

\(\sqrt{3*4} + \sqrt{3*36} + \sqrt{3*16} =\)

\((\sqrt{3}*\sqrt{4}) + (\sqrt{3}*\sqrt{36}) + (\sqrt{3}*\sqrt{16})\)

Take the square roots of the factors that are perfect squares:

\(2\sqrt{3} + 6\sqrt{3} + 4\sqrt{3} =12\sqrt{3}\)

Answer A

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