Since \(\frac{milk}{water} = \frac{24}{25}\), \(\frac{milk}{total}= \frac{24}{49}\)

Portion removed each time = 12.5% = \(\frac{1}{8}\)
Each time \(\frac{1}{8}\) of the total volume is removed, \(\frac{7}{8}\) of the milk remains in the container.
After the removal process is performed 3 times, we get:
\(\frac{milk}{total}= \frac{7}{8} * \frac{7}{8} * \frac{7}{8} * \frac{24}{49} = \frac{21}{64}\)

Of every 64 liters in the container, milk = 21 liters, with the result that water = 64-21 = 43 liters.
Thus:
\(\frac{milk}{water} = \frac{21}{43}\)


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