Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1810:00 AM PDT
-11:00 AM PDT
Join us in a live GMAT practice session and solve 25 challenging GMAT questions with other test takers in timed conditions, covering GMAT Quant, Data Sufficiency, Data Insights, Reading Comprehension, and Critical Reasoning questions.
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products. Ends 6/1
May 1501:00 PM IST
-11:00 AM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.- May 19
12:00 PM PDT
-01:00 PM PDT
Scoring 329 on the GRE is not always about using more books, more courses, or a longer study plan. In this episode of GRE Success Talks, Ashutosh shares his GRE preparation strategy, study plan, and test-day experience, explaining how he kept his prep.... - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
18 Dec 2025, 07:35
Kudos
Bookmarks
Distance,M:Monitoring stn, W: Workshop
W to M, Distance =D, speed s1=45, time t1
M to W, Distance = D, speed s2, time = t2 = 6
Find t1
(1) D= 180, s1=45, hence t1= 180/45 =4. Sufficient
(2) given avg speed=36, and s1, we can find s2. Given s2 and t2, we find D. Given D, s1,we find t1. Sufficient.
W to M, Distance =D, speed s1=45, time t1
M to W, Distance = D, speed s2, time = t2 = 6
Find t1
(1) D= 180, s1=45, hence t1= 180/45 =4. Sufficient
(2) given avg speed=36, and s1, we can find s2. Given s2 and t2, we find D. Given D, s1,we find t1. Sufficient.
18 Dec 2025, 07:40
Kudos
Bookmarks
(1)
Time = Distance/Speed = 180/45 = 4 hours
Sufficient
(2)
2*Distance = AvgSpeed * TotalTime = 36 * (Distance/45 + 6)
Distance = 18/45 * Distance + 18*6 = 2/5 * Distance + 18*6
3/5 * Distance = 18*6
Distance = 36 * 5 = 180
Time = Distance/Speed = 180/45 = 4 hours
Sufficient
The correct answer is D
Time = Distance/Speed = 180/45 = 4 hours
Sufficient
(2)
2*Distance = AvgSpeed * TotalTime = 36 * (Distance/45 + 6)
Distance = 18/45 * Distance + 18*6 = 2/5 * Distance + 18*6
3/5 * Distance = 18*6
Distance = 36 * 5 = 180
Time = Distance/Speed = 180/45 = 4 hours
Sufficient
The correct answer is D
18 Dec 2025, 07:42
Kudos
Bookmarks
What we know is
Speed to station = 45km/h
Time for return trip = 6hrs
Let,
Distance in 1 way = x
Time to reach the station = y
=> y = x/45
We need to find the time y for which we need the distance x here.
Lets go through the statements 1 by 1
Statement (1),
The distance from the workshop to the monitoring station is 180km
=> y = 180/45 = 4hrs
Statement(1) alone is sufficient
Statement (2),
The cart's average speed for the entire round trip is 36km/hr
Average speed = Total distance/Total time
Total distance = 2x
Total time = y + 6
x = 45y
=> 36 = 2x/(y+6)
=> 36 = 90y/(y+6)
=> y = 4
Statement (2) alone is sufficient
D. Each statement alone is sufficient
Speed to station = 45km/h
Time for return trip = 6hrs
Let,
Distance in 1 way = x
Time to reach the station = y
=> y = x/45
We need to find the time y for which we need the distance x here.
Lets go through the statements 1 by 1
Statement (1),
The distance from the workshop to the monitoring station is 180km
=> y = 180/45 = 4hrs
Statement(1) alone is sufficient
Statement (2),
The cart's average speed for the entire round trip is 36km/hr
Average speed = Total distance/Total time
Total distance = 2x
Total time = y + 6
x = 45y
=> 36 = 2x/(y+6)
=> 36 = 90y/(y+6)
=> y = 4
Statement (2) alone is sufficient
D. Each statement alone is sufficient
